calculate x

[man111]

The equation [tex]x+10+6\sqrt{3} = 3\sqrt{1+\sqrt{3}-x}[/tex] has a solution in [tex]x[/tex], then [tex]x=[/tex]

[martin123456]

[tex]a=10+6\sqrt{3}[/tex]
[tex]x^2+2ax+a^2=9(1+\sqrt{3}-x) \Leftrightarrow x^2+2ax+a^2=9+9\sqrt{3}-9x \Leftrightarrow x^2+x(2a+9)+a^2-9-9\sqrt{3}=0[/tex][tex]\Leftrightarrow x^2+x(29+12\sqrt{3})+111\sqrt{3}+199=0[/tex]
I don't think that it has a nice solution