Trigonometry secx+tanx=22/7 cosecx+cotx=?

[man111]

If [tex]secx+tanx = \frac{22}{7}[/tex]. Then find value of [tex]cosecx+cotx =[/tex]

[ganka simeonova]

[tex]secx+tgx=\frac{1+sinx}{ cosx}=\frac{22}{7 } =>\frac{sin{\frac{x}{2 } }+cos{\frac{x}{2 } }}{cos{\frac{x}{2 } } -sin{\frac{x}{2 } }} =\frac{22}{ 7}[/tex]

=>[tex]\frac{cos{\frac{x}{2 } }}{sin{\frac{x}{2 } } } =\frac{29}{15 }[/tex]

[tex]cosecx+ctgx=\frac{1+cosx}{sinx } =\frac{cos{\frac{x}{2 } }}{ sin{\frac{x}{2 } }} =\frac{29}{ 15}[/tex]

[man111]

Thanks. for Nice answer.