от dim » 11 Фев 2010, 11:42
[tex]\sin ^{2}{x} +\sin^{2}{2x}+\sin^{2}{3x}= \frac{3}{2}[/tex] <=> [tex]\frac{3-(\cos{2x}+\cos{4x}+\cos{6x})}{2}=\frac{3}{2}[/tex]<=> [tex]\cos{2x}+\cos{4x}+\cos{6x}=0[/tex]<=> [tex]\cos{4x}+2\cos{4x}\cos{2x}[/tex]<=> [tex]\cos{4x}(2\cos{2x}+1)=0[/tex] .......