от martin123456 » 10 Яну 2013, 13:24
[tex]z=\ln{tg{\frac{x}{y}}[/tex]
[tex]z'|_x=\frac{(tg\frac{x}{y})'}{tg\frac{x}{y}}=\frac{\frac{(\frac{x}{y})'}{\cos^2\frac{x}{y}}}{tg\frac{x}{y}}=\frac{1}{y\cos^2\frac{x}{y}tg\frac{x}{y}}[/tex]
[tex]z'|_y=\frac{(tg\frac{x}{y})'}{tg\frac{x}{y}}=\frac{\frac{(\frac{x}{y})'}{\cos^2\frac{x}{y}}}{tg\frac{x}{y}}=-\frac{x}{y^2\cos^2\frac{x}{y}tg\frac{x}{y}}[/tex]