Задача за вероятност

[Гост]

IMG_20250613_140637.jpg (72.37 KiB) Прегледано 131 пъти

[ammornil]

$\begin{array}{|l|c|c|c|c|c|} \hline i&1&2&3&4&5 \\[6pt] \hline X&20&24&33&35&40 \\[10pt] \hline n&20&22&4&3&1 \\[10pt]\hline p(X)&\dfrac{20}{50}&\dfrac{22}{50}&\dfrac{4}{50}&\dfrac{3}{50}&\dfrac{1}{50} \\[6pt] \hline \end{array} \\[12pt] E(X)= \sum_{i=1}^{5}{[X\cdot{p(X)}]}= 20\cdot{\dfrac{20}{50}}+ 24\cdot{\dfrac{22}{50}} +33\cdot{\dfrac{4}{50}} +35\cdot{\dfrac{3}{50}} +40\cdot{\dfrac{1}{50}} \\[6pt] E(X)= \dfrac{400+ 528+ 132+ 105 +40}{50} = 24,1 \approx 24 $