Разлагане, чрез излагане на общ множител a(x-y)+3(y-x) =

[Гост]

a eto mi gi i zadachite ako mi dadete resheniq shte sum vi mnogo blagodarna
zad1
g) a(x-y)+3(y-x) =
d) (a-b)m+(b-a)n
e) 3(m-2)-(2-m)m

[ammornil]

[tex]a.(x-y)+3.(y-x)=a.(x-y)+3.[-1.(-y+x)]=a.(x-y)-3.(x-y)=(x-y).(a-3)[/tex]

[tex](a-b).m+(b-a).n=(a-b).m-(a-b).n=(a-b).(m-n)[/tex]

[tex]3.(m-2)-(2-m).m=3.(m-2)+(m-2).m=(m-2).(3+m)=(m-2).(m+3)[/tex]