от ammornil » 09 Фев 2024, 17:12
[tex]\angle{BAL}+\angle{ABL}=\angle{ALC} \Rightarrow \angle{BAL}=\angle{ALC}-\angle{ABL}=2x+52^{\circ}-3x=52^{\circ}-x\\ \angle{BAC}=\angle{BAL}+\angle{LAC}=52^{\circ}-x+x=52^{\circ}[/tex]
[tex]\angle{BAL}=\angle{LAC}=x \Rightarrow x=\frac{1}{2}\cdot{52^{\circ}}=26^{\circ} \Rightarrow \angle{ABC}=3\cdot{x}=3\cdot{26^{\circ}}=78^{\circ} \\ \angle{ACB}=180^{\circ}-(\angle{BAC}+\angle{ABC})=180^{\circ}-(52^{\circ}+78^{\circ})=\cdots[/tex]
[tex]\color{lightseagreen}\text{''Който никога не е правил грешка, никога не е опитвал нещо ново.''} \\
\hspace{21em}\text{(Алберт Айнщайн)}[/tex]