- IMG_20240301_155240.jpg (39.3 KiB) Прегледано 2700 пъти
[tex]\triangle{ABD} \rightarrow x+2x=90 \Rightarrow x=30^{\circ} \\ \angle{ABC}=2x=60^{\circ} \\ \angle{ACB}=x+20=50^{\circ} \\ \angle{BAC}=180^{\circ}-(\angle{ABC}+\angle{ACB})=180^{\circ}-110^{\circ}=70^{\circ}[/tex]$$ \boxed{70^{\circ};60^{\circ};50^{\circ}} $$Гост написа:
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