Алгебра

[Гост]

[tex]x[/tex] + 2 - ( [tex]x[/tex]/2 -( ( 3/4+[tex]x[/tex]/4)) = 3- (( 1- ((6-[tex]x[/tex])/3).1/2) /5

[ammornil]

[tex]x[/tex] + 2 - ( [tex]x[/tex]/2 -( ( 3/4+[tex]x[/tex]/4)) = 3- (( 1- ((6-[tex]x[/tex])/3).1/2) /5

[tex]\\[12pt] x+2-\left(\frac{x}{2}-\left(\frac{3}{4}+\frac{x}{4}\right)\right)=3-\dfrac{1-\dfrac{6-x}{3}\cdot{}\dfrac{1}{2}}{5} \\[6pt] x+2-\left(\underbrace{\frac{x}{2}-\frac{3+x}{4}}_{4} \right)=3-\dfrac{\underbrace{1-\dfrac{6-x}{6}}_{6}}{5}\\[6pt] x+2-\left(\frac{2\cdot{x}-(3+x)}{4}\right)=3-\dfrac{\dfrac{6-(6-x)}{6}}{5} \\[6pt] x+2-\left(\frac{2x-3-x}{4}\right)=3-\dfrac{6-6+x}{6\cdot{}5} \\[6pt] \underbrace{\overset{60}{x}+\overset{60}{2}-\frac{\overset{15}{x-3}}{4}=\overset{60}{3}-\frac{\overset{2}{x}}{30}}_{60} \\[6pt] 60\cdot{x}+60\cdot{2}-15\cdot{}(x-3)=60\cdot{3}-2\cdot{x} \\[6pt]60x+120-15x+45-180+2x=0 \\[6pt] 47x=15 \\[6pt] x=\frac{15}{47}[/tex]

Проверете за изчислителни грешки и грешки при пренасянето.

[Гост]

Благодаря!