$\angle{CAM}=\angle{CMA}=x, \quad \angle{CBM}=\angle{CMB}=y \\[6pt] \triangle{AMC} \rightarrow \angle{ACM}=180^{\circ}-2x \\[6pt] \triangle{BMC} \rightarrow \angle{BCM}= 180^{\circ} -2y \\[6pt] \angle{ACM}= \angle{ACB} +\angle{BCM} \Rightarrow 180^{\circ}-2x= 40^{\circ}+180^{\circ}-2y \Leftrightarrow 2y-2x=40^{\circ} \Leftrightarrow y-x=20^{\circ} \\[6pt] \angle{AMB}= \angle{CMB}- \angle{CMA}= y-x =20^{\circ}$