уравнения

[zyzka21]

(x-2)на квадрат=(x-2)(x-3)
(x-3)на квадрат-3(2x+3)=0

[ammornil]

[tex](x-2)^2=(x-2).(x-3) \\
\vspace{10} \\
\cancel{x^2}-2.x.2+2^2=\cancel{x^2}-2.x-3.x+6 \\
-4.x+5.x=6-4 \\
x=2 \\
\vspace{12}\\***\\
(x-3)^2-3.(2.x+3)=0\\
\vspace{10}\\
x^2-2.x.3+3^2-3.2x-3.3=0\\
x^2-6x\cancel{+9}-6x\cancel{-9}=0\\
x^2-12x=0\\
x.(x-12)=0\\
x_{_{1}}=0 \hspace{24} \cup \hspace{24} x-12=0\\
x_{_{1}}=0 \hspace{24} \cup \hspace{24} x_{_{2}}=12[/tex]