Задача 8 клас

[Гост]

[tex][/tex]

[S.B.]

[tex](\frac{3}{\sqrt{2} - \sqrt{5}} + \frac{3}{\sqrt{2} + \sqrt{5}}).\sqrt{8} = (\frac{3(\sqrt{2} + \sqrt{5}) + 3(\sqrt{2} - \sqrt{5})}{(\sqrt{2} - \sqrt{5})(\sqrt{2} + \sqrt{5})}.\sqrt{8} =[/tex]
[tex]\frac{3(\sqrt{2} + \sqrt{5} + \sqrt{2} - \sqrt{5})}{2 - 5}.\sqrt{8} = \frac{6\sqrt{2}}{- 3} . \sqrt{8} = - 2\sqrt{2}.\sqrt{8} = -\sqrt{8}.\sqrt{8} = -8[/tex]