от Xixibg » 25 Окт 2011, 16:08
[tex]a).\frac{1}{\sqrt{3}}+\frac{2}{\sqrt{5}}=[/tex]
[tex]\frac{5\sqrt{3}}{5\sqrt{3}\sqrt{3}}+\frac{2.3\sqrt{5}}{3\sqrt{5}\sqrt{5}}=[/tex]
[tex]\frac{5\sqrt{3}+6\sqrt{5}}{15}[/tex]
[tex]b).\frac{1}{\sqrt{3}-\sqrt{2}}+\frac{2}{\sqrt{5}-2}[/tex]
[tex]\frac{\sqrt{3}+\sqrt{2}}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}+\frac{2(\sqrt{5}+2)}{(\sqrt{5}-2)(\sqrt{5}+2)}=[/tex]
[tex]\sqrt{3}+\sqrt{2}+2(\sqrt{5}+2)[/tex]
[tex]v). \frac{\sqrt{5}}{\sqrt{2}}-\frac{\sqrt{2}}{\sqrt{5}-\sqrt{3}}[/tex]
[tex]\frac{\sqrt{5}\sqrt{2}}{\sqrt{2}\sqrt{2}}-\frac{\sqrt{2}(\sqrt{5}+\sqrt{3})}{(\sqrt{5}-\sqrt{3})(\sqrt{5}+\sqrt{3})}[/tex]
[tex]\frac{\sqrt{5}\sqrt{2}}{2}-\frac{\sqrt{2}(\sqrt{5}+\sqrt{3})}{2}[/tex]
[tex]\frac{-\sqrt{6}}{2}[/tex]