от Consigliere- » 21 Ное 2011, 22:24
Чрез групиране
1. [tex]x^2-(1+\sqrt{3})x+\sqrt{3}=0[/tex]
[tex]x^{2}-x-\sqrt{3}x + \sqrt{3} = 0[/tex]
[tex]x(x-1)-\sqrt{3}(x-1) = 0[/tex]
[tex](x-\sqrt{3})(x-1) = 0[/tex]
[tex]x=\sqrt{3} , x=1[/tex]
2. [tex]x^{2} + (3+\sqrt{2})x + 3\sqrt{2} = 0[/tex]
[tex]x^{2} + 3x + x\sqrt{2} + 3\sqrt{2} = 0[/tex]
[tex]x(x+3) + \sqrt{2}(x+3) = 0[/tex]
[tex](x+\sqrt{2})(x+3) = 0[/tex]
[tex]x=-\sqrt{2} , x=-3[/tex]