Задача

[Гост]

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[tex]\begin{array}{|l} \frac {5x}{y+2} + \frac {3}{x} = 2 \\ \frac {8x}{y+2} + \frac {1}{x} = 7 \end{array}[/tex]
[tex]DM: x \ne 0; y \ne -2[/tex]
Полагаме [tex]\frac {x}{y+2 } = u; \frac {1}{x} = v[/tex]
[tex]\begin{array}{|l} 5u + 3v = 2 \\ 8u +v = 7 \end{array} \Rightarrow -19 u =-19 \Rightarrow u =1 ; v = 7-8u \Rightarrow v=-1[/tex]
[tex]\begin{array}{|l} \frac {x}{y+2} = 1 \\ \frac {1}{x} = -1 \Rightarrow x=-1 \end{array}[/tex]
[tex]-1 = y +2 \Rightarrow y =-3[/tex]
[tex](-1;-3)[/tex]