от mail_dinko » 17 Фев 2012, 14:46
[tex]\frac{\sqrt{12}+\sqrt{75}-\sqrt{108} }{\sqrt{3} }=[/tex]
[tex]=\frac{\sqrt{12}}{\sqrt{3} }+\frac{\sqrt{75} }{\sqrt{3} }-\frac {\sqrt{108} }{\sqrt{3} }=[/tex]
[tex]=\frac{\sqrt{4}. \cancel {\sqrt{3} }}{ \cancel {\sqrt{3} } }+\frac{\sqrt{25}. \cancel {\sqrt{3} } }{ \cancel {\sqrt{3} } }-\frac {\sqrt{36}. \cancel {\sqrt {3}} }{ \cancel {\sqrt{3} }}=[/tex]
[tex]=2+5-6=1[/tex]