sani написа:cos квадрат 70/sin40*cotg110 = ?
[tex]\frac{cos^270}{sin40*cotg110} = \frac{cos^270.sin110}{sin40.cos110} = \frac{sin^220.cos20}{sin40.-sin20} = -\frac{sin20.cos20}{sin40} = -\frac{2sin20.cos20}{2sin40} = -\frac{sin40}{2sin40} = -\frac{1}{2}[/tex]
Навсякъде e градуси.