locus of a curve.

от **man111** » 15 Яну 2011, 05:16

An ellipse slides between two perpendicular straight lines [tex]x = 0[/tex] and [tex]y = 0[/tex] then, locus of it's focii is

от **grav** » 26 Юли 2011, 17:03

I am too lazy to write the computations down, but if i didn't mess them up the answer is

[tex]16x^2y^2=(x^2+y^2)(1+x^2y^2)[/tex]

от **man111** » 27 Дек 2011, 18:14

thanks grav

but how can you get it

от **grav** » 28 Дек 2011, 01:19

It doesn't seem right. It should depend on the ellipse. Now I have to do it again, or for the first time

.