[tex]\int_{0}^{3}\sqrt{\frac{(x+1)^2}{4x}}dx=\int_{0}^{3}(x+1)\frac{1}{2\sqrt{x}}dx=\int_{0}^{3}(x+1)d\sqrt{x}=\frac{a\sqrt{b}}{3}+\sqrt{a}-\frac{b\sqrt{b}}{3}-\sqrt{b}=\frac{3\sqrt{3}}{3}+\sqrt{3}-0=2\sqrt{3}[/tex] - заместваме a и b съответно с 3 и 0.