от aifC » 14 Ное 2017, 21:58
1 зад.
[tex]A \setminus B , B \setminus A \Rightarrow y = 7;,x = 16; \Rightarrow A = \{1,16,3,5,6,8,11\} , B = \{3,5,7,9,10,14\};[/tex]
[tex]A \cap C \Rightarrow \{1,16,3,5,6,8,11\} \cap \{1,2,5,7,9,11,14\} \rightarrow \{1,5,11\};[/tex]
[tex]B \cap C \Rightarrow \{3,5,7,9,10,14\} \cap \{1,2,5,7,9,11,14\} \rightarrow \{5,7,9,14\};[/tex]
[tex]A \cap B \cap C \Rightarrow \{3,5\} \cap \{1,2,5,7,9,11,14\} \rightarrow \{5\};[/tex]
[tex]C \cup B \Rightarrow \{1,2,5,7,9,11,14\} \cup \{3,5,7,9,10,14\} \rightarrow \{1,2,5,7,9,11,14,3,10\};[/tex]
[tex]A \cup B \cup C \Rightarrow \{1,16,3,5,6,8,11\} \cup \{3,5,7,9,10,14\} \cup \{1,2,5,7,9,11,14\} \rightarrow \{1,16,3,5,6,8,11,7,9,10,14,2\};[/tex]
[tex]C \setminus A \Rightarrow \{1,2,5,7,9,11,14\} \setminus \{1,16,3,5,6,8,11\} \rightarrow \{2,7,9,14\};[/tex]
[tex]C \setminus B \Rightarrow \{1,2,5,7,9,11,14\} \setminus \{3,5,7,9,10,14\} \rightarrow \{1,2,11\};[/tex]
[tex]\overline{\rm A} = U \setminus A \Rightarrow \{1,2,3...16\} \setminus \{1,16,3,5,6,8,11\} \rightarrow \{2,4,7,9,10,12,13,14,15\};[/tex]
[tex]\overline{\rm B} = U \setminus B \Rightarrow \{1,2,3...16\} \setminus \{3,5,7,9,10,14\} \rightarrow \{1,2,4,6,8,11,12,13,15,16\};[/tex]
[tex]\overline{\rm C} = U \setminus C \Rightarrow \{1,2,3...16\} \setminus \{1,2,5,7,9,11,14\} \rightarrow \{3,4,6,8,10,12,13,15,16\};[/tex]
На теория няма разлика между теорията и практиката. Но на практика има.