от ammornil » 14 Дек 2021, 00:09
[tex]\begin{array}{|l} {\Large \frac{5x-1}{6} + \frac{3y-1}{10}} = 3 \\{\Large \frac{y+11}{4} - \frac{x-11}{6}} = 3 \end{array}[/tex]
[tex]\begin{array}{|l} 5(5x-1)+3(3y-1)=3.30 \\ 3(y+11)-2(x-11)=3.12 \end{array} \Leftrightarrow \begin{array}{|l} 25x-5+9y-3=90 \\ 3y+33-2x+22=36 \end{array} \Leftrightarrow
\begin{array}{|l} 25x+9y=98 \\ 3y-2x=36-55 \end{array} \Leftrightarrow[/tex]
[tex]\begin{array}{|l}25x+9y=98 \\ -2x+3y=-19 |.(-3) \end{array} \Leftrightarrow \begin{array}{|l}25x+9y+6x-9y=98+57 \\ 3y=2x-19 \end{array} \Leftrightarrow \begin{array}{|l}31x=155 \\ y={\Large \frac{2x-19}{3}} \end{array} \Leftrightarrow[/tex]
[tex]\begin{array}{|l}x=5 \\ y={\Large \frac{2.5-19}{3}} \end{array} \Leftrightarrow \begin{array}{|l}x=5 \\ y=-3 \end{array}[/tex]
[tex]\color{lightseagreen}\text{''Който никога не е правил грешка, никога не е опитвал нещо ново.''} \\
\hspace{21em}\text{(Алберт Айнщайн)}[/tex]