от ammornil » 23 Дек 2023, 11:48
[tex]\overline{ab}=10a+b, \hspace{1em} a \in \mathbb{N}, b \in \mathbb{N}, 0\le b <a \le 9 \\ \phantom{q} \\ \begin{array}{|l} a-b=5 \\ (10a+b)^{2}+(10b+a) ^{2}=3977\end{array}[/tex]
[tex]\begin{array}{|l} a=b+5 \\ (10b+50+b)^{2}+(10b+b+5)^{2}=3977 \end{array} \Leftrightarrow \begin{array}{|l} a=b+5 \\ 121b^{2} + 1100b +2500+121b^{2}+110b+25=3977 \end{array} \Leftrightarrow \begin{array}{|l} a=b+5 \\ 242b^{2} +1210b -1452=0 \end{array} \Leftrightarrow \\ \phantom{q} \\ \Leftrightarrow \begin{array}{|l} a=b+5 \\ 121b^{2}+605b-726=0 \end{array} \\ \phantom{q} \\ \hspace{6em} b_{1,2}=\frac{-605\pm \sqrt{605^{2}-4\cdot{121}\cdot{(-726)}}}{2\cdot{121}}=\frac{-605\pm 847}{242} \rightarrow \begin{cases} b_{1}=1 \in \text{ДМ} \\ b_{2}<0 \notin \text{ДМ} \end{cases} \\ \phantom{q} \\ \begin{array}{|l} a=6 \\ b=1 \end{array}[/tex]
$$ \overline{ab}=61 $$
[tex]\color{lightseagreen}\text{''Който никога не е правил грешка, никога не е опитвал нещо ново.''} \\
\hspace{21em}\text{(Алберт Айнщайн)}[/tex]