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[ammornil]

[tex]\frac{3}{0,75}+\frac{4}{0,85}+\frac{5}{0,95}=\frac{3}{\frac{\normalsize{75}}{\normalsize{100}}}+\frac{4}{\frac{\normalsize{85}}{\normalsize{100}}}+\frac{5}{\frac{\normalsize{95}}{\normalsize{100}}}=\frac{3}{\frac{\normalsize{3}}{\normalsize{4}}}+\frac{4}{\frac{\normalsize{17}}{\normalsize{20}}}+\frac{5}{\frac{\normalsize{19}}{\normalsize{20}}}=\frac{3\cdot 4}{3}+\frac{4\cdot 20}{17}+\frac{5\cdot 20}{19}=\underbrace{\frac{\overset{323}{4}}{1}+\frac{\overset{19}{80}}{17}+\frac{\overset{17}{100}}{19}}_{323}=\frac{4512}{323}=13\frac{313}{323}[/tex]